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x^2+22x-21780=0
a = 1; b = 22; c = -21780;
Δ = b2-4ac
Δ = 222-4·1·(-21780)
Δ = 87604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{87604}=\sqrt{484*181}=\sqrt{484}*\sqrt{181}=22\sqrt{181}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22\sqrt{181}}{2*1}=\frac{-22-22\sqrt{181}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22\sqrt{181}}{2*1}=\frac{-22+22\sqrt{181}}{2} $
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